Class 11 physics, NCERT chapter 4. Attempt each question, check your answer, then open the step-by-step solution.
A $5\ \text{kg}$ block on a smooth horizontal floor is pulled by a $20\ \text{N}$ force acting at $60^\circ$ to the horizontal. Its acceleration is
Answer: (B) $2\ \text{m/s}^2$
Only the horizontal component accelerates the block along the floor.
$$a = \frac{F\cos 60^\circ}{m} = \frac{20 \times 0.5}{5} = 2\ \text{m/s}^2$$
Solution by Sreeraj P, M.Sc Physics
A block is released from rest on a smooth inclined plane as shown. Find the magnitude of its acceleration along the incline in $\text{m/s}^2$. (Take $g = 10\ \text{m/s}^2$.)
Numerical value type. Enter your answer.
Answer: 5
On a smooth incline the only force along the slope is the component of gravity, $mg\sin\theta$.
$$a = g\sin 30^\circ = 10 \times \tfrac12 = 5\ \text{m/s}^2$$
Solution by Sreeraj P, M.Sc Physics
No questions match this filter.