Q 11-04-117JEE MainJEE Main 2023 (15 Apr, Shift 1)Easy
The position vector of a particle related to time $t$ is given by $\vec r=\left(10t\hat i+15t^2\hat j+7\hat k\right)$ m. The direction of net force experienced by the particle is
Answer: (C) Positive $y$-axis
$\vec a=\dfrac{d^2\vec r}{dt^2}=30\hat j\ \text{m s}^{-2}$. The net force is along $\vec a$: the positive $y$-axis.
Solution by Sreeraj P, M.Sc Physics