Q 11-04-119JEE MainJEE Main 2023 (11 Apr, Shift 1)Easy
An average force of $125\ \text{N}$ is applied on a machine gun firing bullets each of mass $10\ \text{g}$ at the speed of $250\ \text{m s}^{-1}$ to keep it in position. The number of bullets fired per second by the machine gun is
Answer: (A) 50
$F=n\,mv\Rightarrow n=\dfrac{125}{0.01\times250}=50$ per second.
Solution by Sreeraj P, M.Sc Physics