Q 11-04-161JEE MainJEE Main 2021 (24 Feb, Shift 1)Easy
The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of the horizontal force that should be applied on the block to keep it adhere to the wall will be ______ N. ($g = 10\ \text{m s}^{-2}$)
Numerical value type. Enter your answer.
Answer: 25
The horizontal force $F$ is the normal reaction. Friction must hold the weight: $\mu F = mg \Rightarrow F = \dfrac{0.5\times10}{0.2} = 25$ N.
Solution by Sreeraj P, M.Sc Physics