Q 11-04-098JEE MainJEE Main 2024 (31 Jan, Shift 2)Easy
A light string passing over a smooth light fixed pulley connects two blocks of masses $m_1$ and $m_2$ hanging vertically. If the acceleration of the system is $\dfrac g8$, then the ratio of the masses $\dfrac{m_1}{m_2}$ ($m_1 > m_2$) is
Answer: (A) $\dfrac97$
$$a = \frac{(m_1 - m_2)g}{m_1 + m_2} = \frac g8 \Rightarrow 8m_1 - 8m_2 = m_1 + m_2 \Rightarrow 7m_1 = 9m_2$$
$\dfrac{m_1}{m_2} = \dfrac97$.
Solution by Sreeraj P, M.Sc Physics