Q 11-04-086JEE MainJEE Main 2024 (29 Jan, Shift 1)Easy
If the radius of curvature of the path of two particles of same mass are in the ratio $3:4$, then in order to have constant centripetal force, their velocities will be in the ratio of:
Answer: (A) $\sqrt3:2$
$F = \dfrac{mv^2}{r}$ is the same for both, so $v^2 \propto r$:
$$\frac{v_1}{v_2} = \sqrt{\frac34} = \frac{\sqrt3}{2}$$
Solution by Sreeraj P, M.Sc Physics