Q 11-04-090JEE MainJEE Main 2024 (9 Apr, Shift 1)Easy
A light unstretchable string passing over a smooth light pulley connects two blocks of masses $m_1$ and $m_2$. If the acceleration of the system is $\dfrac g8$, then the ratio of the masses $\dfrac{m_2}{m_1}$ is:
Answer: (D) $9:7$
Taking $m_2 > m_1$:
$$a = \frac{(m_2 - m_1)g}{m_1 + m_2} = \frac g8 \;\Rightarrow\; 8m_2 - 8m_1 = m_1 + m_2 \;\Rightarrow\; 7m_2 = 9m_1$$
$$\frac{m_2}{m_1} = \frac97$$
Solution by Sreeraj P, M.Sc Physics