Q 11-04-088JEE MainJEE Main 2024 (8 Apr, Shift 1)Easy
A player caught a cricket ball of mass $150\ \text{g}$ moving at a speed of $20\ \text{m/s}$. If the catching process is completed in $0.1\ \text{s}$, the magnitude of force exerted by the ball on the hand of the player is:
Answer: (D) $30\ \text{N}$
$$F = \frac{\Delta p}{\Delta t} = \frac{0.15\times20}{0.1} = 30\ \text{N}$$
Solution by Sreeraj P, M.Sc Physics