Q 11-04-022NEETJEE MainEAMCET 2012 (Engineering)Easy
A vehicle of mass $M$ is moving on a rough horizontal road with a momentum $P$. If the coefficient of friction between the tyres and the road is $\mu$, then the stopping distance is
Answer: (C) $\dfrac{P^2}{2\mu M^2g}$
Retardation $= \mu g$ and initial speed $v = \dfrac{P}{M}$:
$$s = \frac{v^2}{2\mu g} = \frac{P^2}{2\mu M^2g}$$
Solution by Sreeraj P, M.Sc Physics