Q 11-04-022NEETJEE MainEAMCET 2012 (Engineering)Easy
A vehicle of mass $M$ is moving on a rough horizontal road with a momentum $P$. If the coefficient of friction between the tyres and the road is $\mu$, then the stopping distance is
Answer: (C) $\dfrac{P^2}{2\mu M^2g}$
Concept. Retardation $\mu g$, initial speed $\dfrac PM$.
Step 1. Distance. $s = \dfrac{v^2}{2\mu g} = \dfrac{P^2}{2\mu M^2g}$.
Answer. $\dfrac{P^2}{2\mu M^2g}$ (Option C).
Solution by Sreeraj P, M.Sc Physics