Q 11-04-109JEE MainJEE Main 2023 (31 Jan, Shift 2)Easy
A stone of mass $1\ \text{kg}$ is tied to end of a massless string of length $1\ \text{m}$. If the breaking tension of the string is $400\ \text{N}$, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is
Answer: (A) $20\ \text{m s}^{-1}$
The tension supplies the centripetal force: $\dfrac{mv^2}{l}\le400$.
$$v_{max}=\sqrt{\frac{400\times1}{1}}=20\ \text{m s}^{-1}$$
Solution by Sreeraj P, M.Sc Physics