Q 11-04-152JEE MainJEE Main 2022 (27 Jul, Shift 1)Medium
A bag is gently dropped on a conveyor belt moving at a speed of $2\ \text{m s}^{-1}$. The coefficient of friction between the conveyor belt and bag is $0.4$. Initially, the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion is : [Take $g = 10\ \text{m s}^{-2}$]
Answer: (B) $0.5$ m
In the belt's frame the bag starts with speed $2\ \text{m s}^{-1}$ backwards and friction decelerates it at $\mu g = 4\ \text{m s}^{-2}$ until it is at rest on the belt:
$$s = \frac{u^2}{2a} = \frac{2^2}{2\times4} = 0.5\ \text{m}$$
Solution by Sreeraj P, M.Sc Physics