Q 11-04-001NEETEasy
A $5\ \text{kg}$ block on a smooth horizontal floor is pulled by a $20\ \text{N}$ force acting at $60^\circ$ to the horizontal. Its acceleration is
Answer: (B) $2\ \text{m/s}^2$
Only the horizontal component accelerates the block along the floor.
$$a = \frac{F\cos 60^\circ}{m} = \frac{20 \times 0.5}{5} = 2\ \text{m/s}^2$$
Solution by Sreeraj P, M.Sc Physics