Q 11-04-007NEETNEET 2024Top questionEasy
A horizontal force $10$ N is applied to a block $A$ as shown in figure. The mass of blocks $A$ and $B$ are $2$ kg and $3$ kg, respectively. The blocks slide over a frictionless surface. The force exerted by block $A$ on block $B$ is :
Answer: (A) $6$ N
Both blocks move together:
$$a = \frac{F}{m_A + m_B} = \frac{10}{5} = 2\ \text{m s}^{-2}$$
The only horizontal force on $B$ is the push from $A$:
$$F_{AB} = m_B a = 3 \times 2 = 6\ \text{N}$$
Solution by Sreeraj P, M.Sc Physics