Q 11-04-033NEETJEE MainEasy
Three blocks of masses $2$ kg, $3$ kg and $5$ kg are placed in contact in a row on a smooth horizontal floor. A horizontal force of $50$ N pushes the $2$ kg block. The contact force between the $3$ kg and the $5$ kg blocks is
Answer: (B) $25$ N
$a = \dfrac{50}{2 + 3 + 5} = 5\ \text{m/s}^2$.
The contact force on the $5$ kg block is the only horizontal force on it: $N = 5 \times 5 = 25$ N.
Solution by Sreeraj P, M.Sc Physics