Q 11-04-034NEETJEE MainEasy
Masses of $3$ kg and $5$ kg hang at the two ends of a light string passing over a smooth, light pulley. The tension in the string is ($g = 10\ \text{m/s}^2$)
Answer: (C) $37.5$ N
$$T = \frac{2m_1m_2}{m_1 + m_2}g = \frac{2 \times 3 \times 5}{8} \times 10 = 37.5\ \text{N}$$
It lies between the two weights ($30$ N and $50$ N), as it must.
Solution by Sreeraj P, M.Sc Physics