Q 11-04-039NEETJEE MainEasy
A block slides down a rough plane inclined at $37°$ to the horizontal. If $\mu_k = 0.5$, its acceleration is (take $\sin 37° = 0.6$, $g = 10\ \text{m/s}^2$)
Answer: (D) $2\ \text{m/s}^2$
Concept. $a = g(\sin\theta - \mu_k\cos\theta)$.
Step 1. Substitute. $10(0.6 - 0.4) = 2\ \text{m/s}^2$.
Answer. $2\ \text{m/s}^2$ (Option D).
Solution by Sreeraj P, M.Sc Physics