Q 11-04-041NEETJEE MainEasy
A road curve of radius $160$ m is banked so that $\tan\theta = 0.25$. The speed at which a car can take the curve with no need for friction is ($g = 10\ \text{m/s}^2$)
Answer: (B) $20$ m/s
$$v = \sqrt{rg\tan\theta} = \sqrt{160 \times 10 \times 0.25} = \sqrt{400} = 20\ \text{m/s}$$
Solution by Sreeraj P, M.Sc Physics