Q 11-04-144JEE MainJEE Main 2022 (25 Jul, Shift 2)Easy
Two billiard balls of mass $0.05\ \text{kg}$ each moving in opposite directions with $10\ \text{m s}^{-1}$ collide and rebound with the same speed. If the time duration of contact is $t = 0.005\ \text{s}$, then what is the force exerted on the ball due to each other?
Answer: (B) $200\ \text{N}$
Change in momentum of each ball: $\Delta p = 0.05\times(10 + 10) = 1\ \text{kg m s}^{-1}$.
$$F = \frac{\Delta p}{t} = \frac{1}{0.005} = 200\ \text{N}$$
Solution by Sreeraj P, M.Sc Physics