Q 11-04-147JEE MainJEE Main 2022 (26 Jul, Shift 2)Easy
Two masses $M_1$ and $M_2$ are tied together at the two ends of a light inextensible string that passes over a frictionless pulley. When the mass $M_2$ is twice that of $M_1$, the acceleration of the system is $a_1$. When the mass $M_2$ is thrice that of $M_1$, the acceleration of the system is $a_2$. The ratio $\dfrac{a_1}{a_2}$ will be
Answer: (B) $\dfrac23$
$a = \dfrac{(M_2 - M_1)g}{M_1 + M_2}$.
$M_2 = 2M_1$: $a_1 = \dfrac g3$. $M_2 = 3M_1$: $a_2 = \dfrac{2g}{4} = \dfrac g2$. So $\dfrac{a_1}{a_2} = \dfrac23$.
Solution by Sreeraj P, M.Sc Physics