Q 11-04-015NEETJEE MainEAMCET 2013 (Engineering)Easy
A mass $M$ is suspended by a weightless string. The horizontal force required to hold the mass at $60°$ with the vertical is
Answer: (B) $\sqrt{3}\,Mg$
Concept. Equilibrium: $T\sin\theta = F$, $T\cos\theta = Mg$, so $F = Mg\tan\theta$.
Step 1. Substitute. $F = Mg\tan60° = \sqrt3Mg$.
Answer. $\sqrt3Mg$ (Option B).
Solution by Sreeraj P, M.Sc Physics