Q 11-04-015NEETJEE MainEAMCET 2013 (Engineering)Easy
A mass $M$ is suspended by a weightless string. The horizontal force required to hold the mass at $60°$ with the vertical is
Answer: (B) $\sqrt{3}\,Mg$
In equilibrium, with tension $T$ at angle $\theta$ to the vertical:
$$T\sin\theta = F, \qquad T\cos\theta = Mg \;\Rightarrow\; F = Mg\tan\theta$$
$$F = Mg\tan 60° = \sqrt{3}\,Mg$$
Solution by Sreeraj P, M.Sc Physics