Q 11-04-169JEE MainJEE Main 2021 (26 Feb, Shift 1)Easy
A boy pushes a box of mass $2$ kg with a force $\vec{F} = (20\hat{i} + 10\hat{j})$ N on a frictionless surface. If the box was initially at rest, then ______ m is displacement along the $x$-axis after $10$ s.
Numerical value type. Enter your answer.
Answer: 500
$a_x = \dfrac{F_x}{m} = \dfrac{20}{2} = 10$ m s$^{-2}$.
Starting from rest: $x = \frac{1}{2}a_xt^2 = \frac{1}{2}\times10\times10^2 = 500$ m.
Solution by Sreeraj P, M.Sc Physics