Q 11-02-001NEETEasy
A car starts from rest and accelerates uniformly to $20\ \text{m/s}$ in $5\ \text{s}$. The distance it covers in this time is
Answer: (B) $50\ \text{m}$
For uniform acceleration, distance = average velocity × time.
$$s = \frac{u+v}{2}\,t = \frac{0+20}{2}\times 5 = 50\ \text{m}$$
Solution by Sreeraj P, M.Sc Physics