Q 11-02-135NEETNEET 2022Top questionEasy
The ratio of the distances travelled by a freely falling body in the $1^{\text{st}}$, $2^{\text{nd}}$, $3^{\text{rd}}$ and $4^{\text{th}}$ second
Answer: (D) $1 : 3 : 5 : 7$
Distance in the $n^{\text{th}}$ second starting from rest: $s_n = u + \dfrac{g}{2}(2n - 1) = \dfrac{g}{2}(2n-1)$.
For $n = 1, 2, 3, 4$: $\dfrac{g}{2}\times 1,\ 3,\ 5,\ 7$.
Ratio $1 : 3 : 5 : 7$.
Solution by Sreeraj P, M.Sc Physics