Q 11-02-122JEE MainJEE Main 2019 (10 Jan, Shift 2)Easy
A particle starts from the origin at time $t = 0$ and moves along the positive $x$-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time $t = 5\ \text{s}$?
Answer: (B) $9\ \text{m}$
Position $=$ area under the $v$-$t$ graph from $0$ to $5\ \text{s}$:
$0$–$2\ \text{s}$: $\tfrac12\times2\times2 = 2\ \text{m}$
$2$–$4\ \text{s}$: $2\times2 = 4\ \text{m}$
$4$–$5\ \text{s}$: $3\times1 = 3\ \text{m}$
$x = 2 + 4 + 3 = 9\ \text{m}$.
Solution by Sreeraj P, M.Sc Physics