Q 11-02-086JEE MainJEE Main 2023 (6 Apr, Shift 2)Easy
A particle starts with an initial velocity of $10.0\ \text{m s}^{-1}$ along $x$-direction and accelerates uniformly at the rate of $2.0\ \text{m s}^{-2}$. The time taken by the particle to reach the velocity of $60.0\ \text{m s}^{-1}$ is ______.
Answer: (A) 25 s
$t=\dfrac{v-u}{a}=\dfrac{60-10}{2}=25\ \text{s}$.
Solution by Sreeraj P, M.Sc Physics