Q 11-02-047JEE MainJEE Main 2026 (5 Apr, Shift 2)Easy
The velocity ($v$) versus time ($t$) plot of a particle is shown in the figure, for a time interval of $40$ s. The total distance travelled by the particle and the average velocity during this period are, respectively ______.
Answer: (C) $100$ m and zero
Concept. On a $v$–$t$ graph the signed area is the displacement; the sum of the areas taken as positive is the distance. Average velocity $=$ displacement $\div$ time.
Step 1. Areas. From 0 to 20 s: triangle above the axis, $\tfrac12\times20\times5=50$ m. From 20 to 40 s: triangle below, $-50$ m.
Step 2. Distance and displacement. Distance $=50+50=100$ m; displacement $=50-50=0$.
Step 3. Average velocity. $0/40=0$.
Answer. $100$ m and zero (Option C).
Solution by Sreeraj P, M.Sc Physics
