Q 11-02-001NEETEasy
A car starts from rest and accelerates uniformly to $20\ \text{m/s}$ in $5\ \text{s}$. The distance it covers in this time is
Answer: (B) $50\ \text{m}$
Concept. For uniform acceleration, distance $=$ average velocity $\times$ time, with average velocity $\dfrac{u + v}{2}$.
Step 1. Substitute.
$$s = \frac{0 + 20}{2} \times 5 = 50\ \text{m}$$
Answer. $50$ m (Option B).
Solution by Sreeraj P, M.Sc Physics