Q 11-02-040NEETJEE MainMedium
The velocity-time graph of a particle moving along a straight line is shown in the figure. The displacement and the distance travelled by the particle in $6$ s are respectively
Answer: (A) $8$ m, $20$ m
Concept. Displacement $=$ signed area under the $v$–$t$ graph; distance $=$ sum of the magnitudes.
Step 1. Areas. $0$–$2$ s: $+10$ m. $2$–$4$ s: $-6$ m. $4$–$6$ s: $+4$ m.
Step 2. Displacement. $10 - 6 + 4 = 8$ m.
Step 3. Distance. $10 + 6 + 4 = 20$ m.
Answer. $8$ m, $20$ m (Option A).
Solution by Sreeraj P, M.Sc Physics