Q 11-05-111JEE MainJEE Main 2023 (8 Apr, Shift 1)Easy
The momentum of a body is increased by $50\%$. The percentage increase in the kinetic energy of the body is ______ %.
Numerical value type. Enter your answer.
Answer: 125
$K=\dfrac{p^2}{2m}$: $K'=(1.5)^2K=2.25K$, an increase of $125\%$.
Solution by Sreeraj P, M.Sc Physics