Q 11-05-117JEE MainJEE Main 2023 (1 Feb, Shift 2)Easy
A force $F=(5+3y^2)$ acts on a particle in the $y$-direction, where $F$ is in newton and $y$ is in metre. The work done by the force during a displacement from $y=2$ m to $y=5$ m is ______ J.
Numerical value type. Enter your answer.
Answer: 132
$W=\displaystyle\int_2^5(5+3y^2)\,dy=5(3)+(125-8)=132$ J.
Solution by Sreeraj P, M.Sc Physics