Q 11-11-119JEE MainJEE Main 2021 (25 Feb, Shift 1)Easy
A diatomic gas, having $C_P = \frac72 R$ and $C_V = \frac52 R$, is heated at constant pressure. The ratio $dU : dQ : dW$
Answer: (C) 5 : 7 : 2
At constant pressure: $dU = nC_VdT$, $dQ = nC_PdT$, $dW = nR\,dT$.
$$dU : dQ : dW = \tfrac52 : \tfrac72 : 1 = 5 : 7 : 2$$
Solution by Sreeraj P, M.Sc Physics