Q 11-08-051JEE MainJEE Main 2023 (31 Jan, Shift 2)Easy
Under the same load, wire A having length $5.0\ \text{m}$ and cross section $2.5\times10^{-5}\ \text{m}^2$ stretches uniformly by the same amount as another wire $B$ of length $6.0\ \text{m}$ and a cross section of $3.0\times10^{-5}\ \text{m}^2$. The ratio of the Young's modulus of wire $A$ to that of wire $B$ will be
Answer: (B) $1:1$
$Y=\dfrac{FL}{A\,\Delta L}$; with the same $F$ and $\Delta L$, $Y\propto\dfrac LA$.
$$\frac{Y_A}{Y_B}=\frac{5/2.5}{6/3}=\frac22=1$$
Solution by Sreeraj P, M.Sc Physics