Q 11-08-023JEE MainJEE Main 2026 (5 Apr, Shift 1)Easy
A cube has side length $5$ cm and modulus of rigidity $10^5\ \text{N/m}^2$. The displacement produced by a force of $10$ N in the upper face of cube is ______ mm.
Numerical value type. Enter your answer.
Answer: 2
Concept. Shear modulus $\eta=\dfrac{F/A}{\theta}$ with $\theta=\dfrac{\Delta x}{L}$. For a cube, $\Delta x=\dfrac{FL}{\eta A}=\dfrac{F}{\eta L}$.
Step 1. Substitute. $\Delta x=\dfrac{10}{10^5\times0.05}=2\times10^{-3}$ m.
Answer. $2$ mm.
Solution by Sreeraj P, M.Sc Physics
