Q 11-09-011NEETJEE MainEasy
In a hydraulic lift the small and large pistons have areas $10\ \text{cm}^2$ and $500\ \text{cm}^2$. A force of $200$ N on the small piston can support a mass of ($g = 10$ m s$^{-2}$)
Answer: (B) $1000$ kg
Concept. Pascal's law: equal pressure on both pistons, so $F_2 = F_1\dfrac{A_2}{A_1}$.
Step 1. Force. $200 \times 50 = 10^4$ N.
Step 2. Mass. $\dfrac{10^4}{10} = 1000$ kg.
Answer. $1000$ kg (Option B).
Solution by Sreeraj P, M.Sc Physics