Q 11-09-015NEETJEE MainEasy
A solid weighs $60$ N in air and $40$ N when fully immersed in water. The relative density of the solid is
Answer: (B) $3$
Loss of weight $= 20$ N $=$ weight of water displaced (same volume as the solid).
Relative density $= \dfrac{\text{weight in air}}{\text{loss of weight}} = \dfrac{60}{20} = 3$.
Solution by Sreeraj P, M.Sc Physics