Q 11-09-015NEETJEE MainEasy
A solid weighs $60$ N in air and $40$ N when fully immersed in water. The relative density of the solid is
Answer: (B) $3$
Concept. Loss of weight $=$ weight of an equal volume of water; relative density $= \dfrac{\text{weight in air}}{\text{loss of weight}}$.
Step 1. Loss. $60 - 40 = 20$ N.
Step 2. Relative density. $\dfrac{60}{20} = 3$.
Answer. $3$ (Option B).
Solution by Sreeraj P, M.Sc Physics