Q 11-09-017NEETJEE MainMedium
Water flows through a horizontal pipe. At point P its speed is $2$ m s$^{-1}$ and at point Q it is $4$ m s$^{-1}$. The pressure at P exceeds that at Q by
Answer: (D) $6000$ Pa
Concept. Bernoulli for a horizontal pipe: $p_P - p_Q = \dfrac12\rho(v_Q^2 - v_P^2)$.
Step 1. Substitute. $\dfrac12 \times 1000 \times (16 - 4) = 6000$ Pa.
Answer. $6000$ Pa (Option D).
Solution by Sreeraj P, M.Sc Physics