Q 11-09-017NEETJEE MainMedium
Water flows through a horizontal pipe. At point P its speed is $2$ m s$^{-1}$ and at point Q it is $4$ m s$^{-1}$. The pressure at P exceeds that at Q by
Answer: (D) $6000$ Pa
Bernoulli's equation for a horizontal pipe:
$p_P - p_Q = \dfrac{1}{2}\rho(v_Q^2 - v_P^2) = \dfrac{1}{2} \times 1000 \times (16 - 4) = 6000$ Pa.
Solution by Sreeraj P, M.Sc Physics