Q 11-14-058JEE MainJEE Main 2023 (11 Apr, Shift 1)Easy
The equation of wave is given by $Y=10^{-2}\sin\left[2\pi(160t-0.5x)+\dfrac\pi4\right]$, where $x$ and $Y$ are in m and $t$ in s. The speed of the wave is ______ $\text{km h}^{-1}$.
Numerical value type. Enter your answer.
Answer: 1152
$v=\dfrac{\omega}{k}=\dfrac{2\pi\times160}{2\pi\times0.5}=320\ \text{m s}^{-1}=320\times3.6=1152\ \text{km h}^{-1}$.
Solution by Sreeraj P, M.Sc Physics