Q 11-14-065JEE MainJEE Main 2023 (8 Apr, Shift 1)Easy
An organ pipe $40$ cm long is open at both ends. The speed of sound in air is $360\ \text{m s}^{-1}$. The frequency of the second harmonic is ______ Hz.
Numerical value type. Enter your answer.
Answer: 900
Open pipe: $f_n=\dfrac{nv}{2L}$, so $f_2=\dfrac{2\times360}{2\times0.4}=900$ Hz.
Solution by Sreeraj P, M.Sc Physics