Q 11-11-104JEE MainJEE Main 2022 (25 Jul, Shift 1)Medium
A certain amount of gas of volume $V$ at $27^\circ\text{C}$ temperature and pressure $2\times10^7\ \text{N m}^{-2}$ expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Use $\gamma = 1.5$)
Answer: (B) $3.536\times10^6\ \text{Pa}$
Isothermal doubling: $P_1 = \dfrac{2\times10^7}{2} = 10^7\ \text{Pa}$.
Adiabatic doubling: $P_2 = P_1\left(\dfrac12\right)^{1.5} = \dfrac{10^7}{2\sqrt2}\approx3.536\times10^6\ \text{Pa}$.
Solution by Sreeraj P, M.Sc Physics