Thermodynamics question for JEE Main (JEE Main 2022 (25 Jul, Shift 2)), with solution

Let $\eta_1$ be the efficiency of an engine at $T_1 = 447^\circ\text{C}$ and $T_2 = 147^\circ\text{C}$ while $\eta_2$ is the efficiency at $T_1 = 947^\circ\text{C}$ and $T_2 = 47^\circ\text{C}$. The ratio $\dfrac{\eta_1}{\eta_2}$ will be