Q 11-11-001NEETEasy
A Carnot engine works between a source at $500\ \text{K}$ and a sink at $300\ \text{K}$. Its efficiency is
Answer: (A) $40\%$
Concept. Carnot efficiency $\eta = 1 - \dfrac{T_2}{T_1}$.
Step 1. Substitute. $1 - \dfrac{300}{500} = 0.4 = 40\%$.
Answer. $40\%$ (Option A).
Solution by Sreeraj P, M.Sc Physics