Q 11-11-001NEETEasy
A Carnot engine works between a source at $500\ \text{K}$ and a sink at $300\ \text{K}$. Its efficiency is
Answer: (A) $40\%$
$$\eta = 1 - \frac{T_2}{T_1} = 1 - \frac{300}{500} = 0.4 = 40\%$$
Solution by Sreeraj P, M.Sc Physics