Q 11-11-006NEETNEET 2023Top questionEasy
A Carnot engine has an efficiency of $50\%$ when its source is at a temperature $327°$ C. The temperature of the sink is :
Answer: (A) $27°$ C
$T_1 = 327 + 273 = 600$ K.
$$\eta = 1 - \frac{T_2}{T_1} \;\Rightarrow\; 0.5 = 1 - \frac{T_2}{600} \;\Rightarrow\; T_2 = 300\ \text{K} = 27°\text{C}$$
Solution by Sreeraj P, M.Sc Physics