Q 11-11-010JEE MainAIEEE 2007Easy
When a system is taken from state $i$ to state $f$ along the path $iaf$, it is found that $Q = 50$ cal and $W = 20$ cal. Along the path $ibf$, $Q = 36$ cal. $W$ along the path $ibf$ is
Answer: (B) $6$ cal
$\Delta U$ depends only on the end states. Along $iaf$: $\Delta U = 50 - 20 = 30$ cal.
Along $ibf$: $W = Q - \Delta U = 36 - 30 = 6$ cal.
Solution by Sreeraj P, M.Sc Physics