Q 11-11-015NEETJEE MainEAMCET 2008 (Medical)Easy
One mole of an ideal gas undergoes an isothermal change at temperature $T$ so that its volume $V$ is doubled. $R$ is the molar gas constant. The work done by the gas during this change is
Answer: (B) $RT\log 2$
$$W = nRT\ln\frac{V_2}{V_1} = RT\ln 2$$
Solution by Sreeraj P, M.Sc Physics