Q 11-11-015NEETJEE MainEAMCET 2008 (Medical)Easy
One mole of an ideal gas undergoes an isothermal change at temperature $T$ so that its volume $V$ is doubled. $R$ is the molar gas constant. The work done by the gas during this change is
Answer: (B) $RT\log 2$
Concept. Isothermal work: $W = nRT\ln\dfrac{V_2}{V_1}$.
Step 1. Substitute. $W = RT\ln2$.
Answer. $RT\log2$ (Option B).
Solution by Sreeraj P, M.Sc Physics