Q 11-11-017JEE MainAIEEE 2011Easy
$100$ g of water is heated from $30°$C to $50°$C. Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is $4184$ J/kg K)
Answer: (D) $8.4$ kJ
Concept. Ignoring the tiny expansion, no work is done, so $\Delta U=Q=mc\Delta T$.
Step 1. Substitute. $0.1\times4184\times20=8368$ J $\approx8.4$ kJ.
Answer. Option D.
Solution by Sreeraj P, M.Sc Physics


