An ideal gas at 27°C is compressed adiabatically to (1)/(8) of its original volume. If γ = (5)/(3), its final temperature is

(A) 1200 K. TV^γ - 1 = constant: T_2 = T_1((V_1)/(V_2))^γ - 1 = 300 × 8^2/3 = 300 × 4 = 1200 K.

Thermodynamics question for NEET / JEE Main, with solution

Q 11-11-022NEETJEE MainMedium

An ideal gas at $27°$C is compressed adiabatically to $\dfrac{1}{8}$ of its original volume. If $\gamma = \dfrac{5}{3}$, its final temperature is