Q 11-06-026NEETJEE MainEasy
Masses of $1$ kg, $2$ kg and $3$ kg are placed at the points $(0, 0)$, $(2, 0)$ and $(0, 2)$ m respectively. The position of their centre of mass is
Answer: (D) $\left(\dfrac{2}{3},\ 1\right)$ m
$$x_{cm} = \frac{1(0) + 2(2) + 3(0)}{6} = \frac{2}{3}\ \text{m}, \qquad y_{cm} = \frac{1(0) + 2(0) + 3(2)}{6} = 1\ \text{m}$$
Solution by Sreeraj P, M.Sc Physics