Q 11-06-029NEETJEE MainEasy
The moment of inertia of a uniform ring of mass $M$ and radius $R$ about a tangent in its plane is
Answer: (C) $\dfrac{3}{2}MR^2$
About a diameter: $\dfrac{MR^2}{2}$ (perpendicular axis theorem: two diameters add to $MR^2$).
Parallel axis theorem for the tangent in the plane:
$$I = \frac{MR^2}{2} + MR^2 = \frac{3}{2}MR^2$$
Solution by Sreeraj P, M.Sc Physics