Q 11-06-030NEETJEE MainEasy
The radius of gyration of a uniform rod of length $L$ about an axis perpendicular to it and passing through one end is
Answer: (D) $\dfrac{L}{\sqrt{3}}$
$I = \dfrac{ML^2}{3} = Mk^2$, so $k = \dfrac{L}{\sqrt{3}}$.
Solution by Sreeraj P, M.Sc Physics