Q 12-14-185JEE MainJEE Main 2019 (9 Apr, Shift 2)Easy
The logic gate equivalent to the given logic circuit is
Answer: (D) OR
The inputs are inverted and then fed to a NAND gate:
$$Y = \overline{\bar A\cdot\bar B} = \bar{\bar A} + \bar{\bar B} = A + B$$
(De Morgan's theorem). This is an OR gate.
Solution by Sreeraj P, M.Sc Physics